What is the amperage of a rectifier with a shunt factor of 0.5 and a measured voltage of 24 mV?

Prepare for the NCCER Pipeline Corrosion Control Test. Study with flashcards and multiple-choice questions, each question provides hints and explanations. Ace your exam!

To determine the amperage of a rectifier given the shunt factor and measured voltage, you can apply the formula that relates these values together. The amperage (I) can be calculated by rearranging the standard formula:

[ I = \frac{V}{Shunt\ Factor} ]

In this case, the voltage measured is 24 mV, which can be converted to volts by recognizing that 1 volt equals 1000 millivolts. Therefore, 24 mV is 0.024 V. Given a shunt factor of 0.5, you would substitute this into the formula:

[ I = \frac{0.024 V}{0.5} ]

When you perform the calculation, you find:

[ I = 0.048 A ]

To convert this current from amperes to milliamperes (since 1 A = 1000 mA), you multiply by 1000:

[ 0.048 A \times 1000 = 48 mA ]

The result of 48 mA does not correspond to the options provided directly in terms of amperes. However, reviewing the context of the problem, it implies that the measured voltage is contributing to

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy