What is the amperage of a rectifier with a shunt factor of 2 and a measured voltage of 24 mV?

Prepare for the NCCER Pipeline Corrosion Control Test. Study with flashcards and multiple-choice questions, each question provides hints and explanations. Ace your exam!

To find the amperage of a rectifier using a shunt factor and measured voltage, you can apply the formula:

Amperage (I) = Measured Voltage (V) / Shunt Factor.

In this case, the measured voltage is 24 millivolts (mV), which is equivalent to 0.024 volts (V), and the shunt factor is 2. By substituting these values into the formula, you calculate as follows:

Amperage = 0.024 V / 2 = 0.012 A, or 12 mA.

However, since none of the provided choices correspond to 12 mA directly, the number seems to relate to the interpretation of those units. Considering rectifiers are often discussed in higher ranges, if we consider these values in a context where the shunt factor and measurements are interpreted or organized differently, it could align with any context—thus leading to a likely misunderstanding of the anticipated reading.

The correct amperage here aligns with 24 mV considered at a shunt factor of 2 resulting in 12, where it seems your answer was based on factors not directly illustrated in the described scenario presented. Each potential answer increases based on varying understanding of unit

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